Normalization process
SSC conducts various exams like SSC CGL, SSC CHSL, SSC MTS, and some more.
Students participating in these exams are lakhs in number, So SSC has to conduct exams in different shifts and on different dates. Every shift of the exam has different questions so it becomes almost impossible to balance the difficulty level for every shift. Now Normalization is the process that balances the difficulty level either by increasing or decreasing(as required) the raw marks obtained by a student in a particular shift.
If we simply Understand how normalization works, So it brings the average marks of every shift to almost equal.
Here is an example,
If we take an exam in 2 shifts, In shift 1 A, B, C, D, and E participated and In shift 2 P, Q, R, S, and T participated.
Marks In shift 1- A-60,B-70,C-65,D-55,E-50,
So average mark in shift 1 is 60.
Marks In Shift 2 - P-80,Q-90,R-85,S-75,T-80
So the average mark in shift 2 is 82.
Now we see that the average marks of shift 1 are lesser than that of shift 2. It means shift 1 was tough as
compared to shift 2( as SSC follows that each shift has equal talent pull). So the marks of shift 1 student
will be increased. That’s what Normalization is.
Now the question is that how many marks will be increased? So for that SSC uses a Standard formula.
Mij = Normalized marks of the jth candidate in the ith shift.
Mtg = is the average marks of the top 0.1% of the candidates considering all shifts (number of candidates will be rounded up).
Mqg = is the sum of mean and standard deviation marks of the candidates in the examination considering all shifts.
Mti = is the average marks of the top 0.1% of the candidates in the ith shift (number of candidates will be rounded up).
Miq = is the sum of mean marks and standard deviation of the ith shift.
